If you believe the fluorescence emission comes from higher excited state than S1 (e.g. S2), you should optimize the corresponding excited state and perform the analysis again.
]]>2 Emission strength is positively proportional to square of norm of transition dipole moment (please check equation of evaluating oscillator strength). So, sign of transition dipole moment is unimportant.
]]>The result of the overlaps between electron and hole was higher for the pure graphene. And the transition dipole moments were:
Transition dipole moment in X/Y/Z: -0.001971 -2.531006 -0.000003 a.u. (Pure graphene)
Transition dipole moment in X/Y/Z: 0.090665 0.026479 0.361728 a.u (Graphene with OH group)
But the experimentation shows that functionalized graphene has a higher fluorescence intensity. I have two questions:
1) I should've used the output of the fluorescence for this analysis?
2) The negative transition dipole moment of graphene means that the graphene with the OH graphene would have higher fluorescence intensity?